[SQRT(2x^2+6x+4)]=x+1

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Solution for [SQRT(2x^2+6x+4)]=x+1 equation: 


Simplifying
[SQRT(2x2 + 6x + 4)] = x + 1

Reorder the terms:
[QRST(4 + 6x + 2x2)] = x + 1
[(4 * QRST + 6x * QRST + 2x2 * QRST)] = x + 1
[(4QRST + 6xQRST + 2x2QRST)] = x + 1
[4QRST + 6xQRST + 2x2QRST] = x + 1

Remove brackets around [4QRST + 6xQRST + 2x2QRST]
4QRST + 6xQRST + 2x2QRST = x + 1

Reorder the terms:
4QRST + 6xQRST + 2x2QRST = 1 + x

Solving
4QRST + 6xQRST + 2x2QRST = 1 + x

Solving for variable 'Q'.

Move all terms containing Q to the left, all other terms to the right.

Reorder the terms:
-1 + 4QRST + -1x + 6xQRST + 2x2QRST = 1 + x + -1 + -1x

Reorder the terms:
-1 + 4QRST + -1x + 6xQRST + 2x2QRST = 1 + -1 + x + -1x

Combine like terms: 1 + -1 = 0
-1 + 4QRST + -1x + 6xQRST + 2x2QRST = 0 + x + -1x
-1 + 4QRST + -1x + 6xQRST + 2x2QRST = x + -1x

Combine like terms: x + -1x = 0
-1 + 4QRST + -1x + 6xQRST + 2x2QRST = 0

The solution to this equation could not be determined.

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